PAT (Basic Level) Practice （中文） 1012 数字分类

Posted 2021-03-01 learn-excel

 1 #include<cstdio>
 2 using namespace std;
 3 int num[5],sumn[5],n;
 4 void init();
 5 void read();
 6 void deal();
 7 int main(){
 8     init();
 9     read();
10     deal();
11     return 0;
12 }
13 void init(){
14     for(int i=0;i<=4;i++){
15         num[i] = 0;
16         sumn[i] = 0;
17     }
18     return ;
19 }
20 void read(){
21     int data,flag=-1;
22     scanf("%d",&n);
23     for(int i=1;i<=n;i++){
24         scanf("%d",&data);
25         switch(data%5){
26             case 0:  //偶数和
27                 if(data%2==0) {num[0]++;sumn[0]+=data;}
28                 break;
29             case 1:  //出顺序进行交错求和
30                 num[1]++;
31                 sumn[1]+=((-1)*flag*data);
32                 flag = -flag;
33                 break;
34             case 2:   //数字的个数
35                 num[2]++;break;
36             case 3:  //数字的平均数
37                 num[3]++;
38                 sumn[3]+=data;
39                 break;
40             case 4:  //数字中最大数字
41                 num[4]++;
42                 if((num[4]>1&&sumn[4]<data)||(num[4]==1)) sumn[4] = data;
43                 break;
44         }
45     }
46 }
47 void deal(){
48     if(num[0]==0) printf("N ");
49     else printf("%d ",sumn[0]);
50 
51     if(num[1]==0) printf("N ");
52     else printf("%d ",sumn[1]);
53 
54     if(num[2]==0) printf("N ");
55     else printf("%d ",num[2]);
56 
57     if(num[3]==0)  printf("N ");
58     else printf("%.1f ",((float)(sumn[3])/num[3]));
59 
60     if(num[4]==0)  printf("N");
61     else printf("%d",sumn[4]);
62 
63 }

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