列表的索引/元素#'；s

Posted 2021-02-26

>>> a = [2, 9, 17, 3]
>>> for index, workwith in enumerate(a):
...     print "element", index, "is", workwith
... 
element 0 is 2
element 1 is 9
element 2 is 17
element 3 is 3
>>>