按周和年获取日期

Posted 2021-02-26

/**
* @param Int $week
* @param Int $year
* @return Array
*/

public function getDaysInWeek($week, $year) {
        $week = sprintf('%02d',$week); //format as a 2 digit number. eg: 05
 
        // set up ISO week date, eg: 2006W527, sunday(7), week 52 of 2006
        $daysInWeek = array();
        for ($day = 1;
        $day <= 7;
        $day++) {
            $ISOweekDate = $year . "W" . $week . $day;
            $daysInWeek[] = strtotime($ISOweekDate);
        }
 
        return $daysInWeek;
    }