从输入文件创建zipfile

Posted 2021-02-25

This creates a zipfile with the same name as the input file in the same location as the input file. Only does a single file.

import zlib, zipfile, os
 
def zipme (inputFilename):
    fileName = os.path.basename(inputFilename)
    zipFileName = os.path.basename (os.path.splitext(fileName)[0]) + '.zip'
    zipFilePath = os.path.dirname (inputFilename)
    zFile = zipfile.ZipFile(zipFilePath + '/' + zipFileName ,'w')
    zFile.write (inputFilename, fileName, zipfile.ZIP_DEFLATED)
    zFile.close()
    if os.stat(zipFileName):
        print 'zipfile created : %s' % (zipFileName)
        return 1
    else :
        print 'Error creating zipfile : %s' % (zipFileName)
        return 0