命题逻辑角形知识库的人工智能反向链接实现

Posted 2021-02-24

Artificial intelligence basics : This is a backward chaining implementation which works with horn form knowledge bases. Had some trouble finding any simple and easy to understand examples online - so here's my version!!! http://en.wikipedia.org/wiki/Backward_chaining

import java.util.*;
import java.io.*;
 
// to run simply do a: new BC(ask,tell) and then bc.execute()
// ask is a propositional symbol
// and tell is a knowledge base
// ask : p
// tell : p=>q;q=>r;r;
 
class BC{
// create variables
public static String tell;
public static String ask;
public static ArrayList<String> agenda;
public static ArrayList<String> facts;
public static ArrayList<String> clauses;
public static ArrayList<String> entailed;
 
public BC(String a, String t){
	// initialize variables
	agenda  = new ArrayList<String>();
	clauses  = new ArrayList<String>();
	entailed  = new ArrayList<String>();
	facts  = new ArrayList<String>();
	tell = t;
	ask = a;
	init(tell);
}
 
 
// method which sets up initial values for backward chaining
public static void init(String tell){
	agenda.add(ask);
	// split kb into sentences
   String[] sentences = tell.split(";");
	for (int i=0;i<sentences.length;i++){
		if (!sentences[i].contains("=>")) 
			// add the facts
			facts.add(sentences[i]);
		else{
			// add the premises	
			clauses.add(sentences[i]);
			}
	}
}
 
// method which calls the main bcentails() method and returns output back to iengine
public String execute(){
	String output = "";
 
	if (bcentails()){
		// the method returned true so it entails
		output = "YES: ";
		// loop through all entailed symbols in reverse
		for (int i=entailed.size()-1;i>=0;i--){
				if (i==0)
					output += entailed.get(i);
				else	
					// no comma at the end
					output += entailed.get(i)+", ";
 
			}
	}
	// no 
	else{
			output = "NO";
	}
	return output;		
}
 
// method which runs the bc algorithm
public boolean bcentails(){
	// while the list of symbols are not empty
	while(!agenda.isEmpty()){
		// get current symbol
		String q = agenda.remove(agenda.size()-1);
		// add the entailed array
		entailed.add(q);
 
		// if this element is a fact then we dont need to go further
		if (!facts.contains(q)){
			// .. but it isnt so..
			// create array to hold new symbols to be processed 
			ArrayList<String> p = new ArrayList<String>();
			for(int i=0;i<clauses.size();i++){
			// for each clause..
					if (conclusionContains(clauses.get(i),q)){
					// that contains the symbol as its conclusion
 
							ArrayList<String> temp = getPremises(clauses.get(i));
							for(int j=0;j<temp.size();j++){
								// add the symbols to a temp array
								p.add(temp.get(j));
							}
						}						
			}
			// no symbols were generated and since it isnt a fact either 
			// then this sybmol and eventually ASK  cannot be implied by TELL
			if (p.size()==0){
				return false;
			}
			else{
					// there are symbols so check for previously processed ones and add to agenda
					for(int i=0;i<p.size();i++){
							if (!entailed.contains(p.get(i)))
									agenda.add(p.get(i));
							}
 
 
			}
		}
 
	}//while end
	return true;
}
 
// methid that returns the conjuncts contained in a clause
public static ArrayList<String> getPremises(String clause){
	// get the premise
	String premise = clause.split("=>")[0];
	ArrayList<String> temp = new ArrayList<String>();
	String[] conjuncts = premise.split("&");
	// for each conjunct
	for(int i=0;i<conjuncts.length;i++){
			if (!agenda.contains(conjuncts[i]))
					temp.add(conjuncts[i]);
	}
	return temp;
}
 
 
// method which checks if c appears in the conclusion of a given clause	
// input : clause, c
// output : true if c is in the conclusion of clause
public static boolean conclusionContains(String clause, String c){
	String conclusion = clause.split("=>")[1];
	if (conclusion.equals(c))
		return true;
	else
		return false;
 
}
 
}