密码强度检查器
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了密码强度检查器相关的知识,希望对你有一定的参考价值。
This is based on the javascript snippet at the snipplr URL listed. It in turn referenced a page that is no longer available. So I have decided to make my pythonification of the JavaScript available for others instead of hoarding it.
""" Class for checking the strength of a password. Copyright (C) 2011 Henry Longmore. This version of this file may be copied for personal, educational, or commercial purposes. Use at your own risk. """ import os from os import path import math # Nota Bene: the configuration module is non-standard. You will # need to format and read your dictionary file yourself. from djangoapps import configuration password_dict = path.join(os.sep, 'path', 'to', 'your', 'password.dictionary') # Based on Password Strength Meter posted at Snipplr # http://snipplr.com/view/8755/password-strength-meter/ class PasswordStrengthChecker(object): def __init__(self, strength='medium', pwd_dict=''): self.similarity_map = { '3': 'e', 'x': 'k', '5': 's', '$': 's', '6': 'g', '7': 't', '8': 'b', '|': 'l', '9': 'g', '+': 't', '@': 'a', '0': 'o', '1': 'l', '2': 'z', '!': 'i', '1': 'i'} password_dictionary = configuration.Configuration(configpath=pwd_dict) self.word_list = dict() for i in xrange(3, 17): self.word_list[i] = password_dictionary.get_option('%s' % i, []) self.strengths = ['medium', 'strong', 'best'] self.thresholds = {'medium': 0.8, 'strong': 0.6, 'best': 0.6} self.min_length = {'medium': 8, 'strong': 8, 'best': 14} self.min_charsets = {'medium': 2, 'strong': 3, 'best': 3} self.similarity = {'medium': False, 'strong': True, 'best': True} if strength not in self.strengths: strength = self.strengths[0] self.strength = strength def is_charset_type(self, c, c_class): if c_class == 'capital': return c.isalpha() and c == c.upper() if c_class == 'lower': return c.isalpha() and c == c.lower() if c_class == 'digit': return c.isdigit() if c_class == 'punctuation': return c in self.punctuation return False def canonicalize_word(self, word, letters_only=False): canonicalized = '' for c in list(word.lower()): if letters_only and not self.is_charset_type(c, 'lower'): canonicalized += c else: canonicalized += self.similarity_map.get(c, c) return canonicalized def charset_span(self, word): checks = {'capital': 0, 'lower': 0, 'digit': 0, 'punctuation': 0} for c in list(word): for key in checks: if not checks[key] and self.is_charset_type(c, key): checks[key] = 1 break return sum(checks.values()) def in_dictionary(self, word): similarity_check = self.similarity[self.strength] canonicalized = self.canonicalize_word(word, letters_only=similarity_check) word_length = len(canonicalized) if canonicalized in self.word_list[word_length]: return True if similarity_check: minimum_meaningful_match = int(math.floor((self.thresholds[self.strength]) * word_length)) for length in xrange(minimum_meaningful_match, word_length): for start in xrange(0, word_length - minimum_meaningful_match): subword = canonicalized[start:start + length] if subword in self.word_list[len(subword)]: return True return False def strong_enough(self, password): if not password: return False if len(password) < self.min_length[self.strength]: return False if self.charset_span(password) < self.min_charsets[self.strength]: return False if self.in_dictionary(password): return False return True global password_checker password_checker = PasswordStrengthChecker(strength='medium', pwd_dict=password_dict)
以上是关于密码强度检查器的主要内容,如果未能解决你的问题,请参考以下文章
[LeetCode] Strong Password Checker 密码强度检查器
Python练习题9(密码判断):请写一个密码安全性检查的代码代码: 首先判断密码的强度,如果结果是低或中则打印如何提升密码安全级别的提示,而高则直接退出