根据折线经纬度获取的折线平行线

Posted 2020-11-12 seeyou1993

 

/** 
* @Title: main 
* @Description: TODO(经纬度根据获取折线的平行线) 
* @param list 平行线
* @param angle （公里数）距离真实线范围 经纬度大概按照0.0011为100米进行计算
* @return List<Double[]> 平行线坐标数组{0:lon,1:lat}
* @throws 
*/ 
public static List<Double[]> getParallelLine(List<Map<String, Object>> list, double angle) {
List<Double[]> listd = new ArrayList<>();
for (int i = 1; i < list.size() - 1; i++) {

/*后一个点*/
Map<String, Object> map_1 = list.get(i + 1);
Double[] result_1 = getTrueGrod(map_1);
Double lon_1 = result_1[0];
Double lat_1 = result_1[1];

/*中间一个点*/
Map<String, Object> map = list.get(i);
Double[] result = getTrueGrod(map);
Double lon = result[0];
Double lat = result[1];

/*前一个点*/
Map<String, Object> map_2 = list.get(i - 1);
Double[] result_2 = getTrueGrod(map_2);
Double lon_2 = result_2[0];
Double lat_2 = result_2[1];
//System.out.println(angle * 1000 / 100 * 0.00105+"经纬度");
Double[] result_t = getResuleGrod(lon, lat, lon_1, lat_1, lon_2, lat_2, angle * 10 * 0.0011);
listd.add(result_t);
}
return listd;

}

/** 
* @Title: getResuleGrod 
* @Description: TODO(根据三个点获取顶点经纬度位置) 
* @return Double[] 
* @throws 
*/ 
private static Double[] getResuleGrod(double x, double y, double x1, double y1, double x2, double y2, double t) {
if (y2 - y == 0 || y - y == 0)
y = y - 0.0000001;
double angle1 = Math.atan(x2 - x / y2 - y);
double angle2 = Math.atan(x - x1 / y - y1);

double angle3 = 0.5 * (angle2 - angle1 - Math.PI);
double angle4 = angle1 + angle3;
double distance = t / Math.sin(angle3);
x = x + distance * Math.cos(angle4);
y = y + distance * Math.sin(angle4);
Double[] result = new Double[] { x , y };
return result;
}