714. 买卖股票的最佳时机含手续费

Posted 2021-02-20 yuhong1103

 1 class Solution 
 2 {
 3 public:
 4     int maxProfit(vector<int>& prices, int fee) 
 5     {
 6         int n = prices.size();
 7         vector<vector<int>> dp(n,vector<int>(2,0));
 8 
 9         dp[0][0] = 0;
10         dp[0][1] = -prices[0];
11         for(int i = 1;i < n;i ++)
12         {
13             dp[i][0] = max(dp[i - 1][0],dp[i - 1][1] + prices[i] - fee);//没有持有
14             dp[i][1] = max(dp[i - 1][1],dp[i - 1][0] - prices[i]);//持有
15         }
16         return dp[n - 1][0];
17     }
18 };