模拟与高精度 P1042 乒乓球

Posted 2021-02-20 jason66661010

题目

https://www.luogu.com.cn/problem/P1042

题目分析

直到分差大于或者等于2,才一局结束：意思就是即使有人先得了1分，但是两人分差<2也不算结束，要继续比赛，直到分差大于或者等于2才这局结束

代码

#include<iostream>
#include<cstdio>
#include<string>
#include<cstring>
#include<cmath>
#include<vector>
using namespace std;
typedef pair<int, int> p;
vector<p>list;
int main()
{
    char tmp;
    int a=0, b=0;
    int a2 = 0, b2 = 0;
    int count1a = 0,count1b=0,count2a=0, count2b = 0;
    while (1)
    {
        scanf("%c", &tmp);
        if (tmp == ‘E‘)
        {
            printf("%d:%d
", a, b);
            p temp = make_pair(a2, b2);
            list.push_back(temp);
            break;
        }
        if (tmp == ‘W‘) { a++; a2++; count1a++; count2a++; }
        if (tmp == ‘L‘) { b++; b2++; count1b++; count2b++; }
        if (abs(a - b) >= 2 && (count1a >= 11||count1b>=11))
        {
            printf("%d:%d
", a, b);
            a = 0; b = 0; count1a = 0; count1b = 0;
        }
        if (abs(a2 - b2) >= 2 && (count2a >= 21 || count2b >= 21))
        {
            p temp = make_pair(a2, b2);
            list.push_back(temp);
            a2 = 0; b2 = 0; count2a = 0; count2b = 0;
        }


    }
    printf("
");
    for (int i = 0; i < list.size();i++)
        printf("%d:%d
", list[i].first, list[i].second);
}