1017. A除以B (20)

Posted 2021-02-17 mqxnongmin

版权声明： https://blog.csdn.net/oFengWuYu1/article/details/25612231

本题要求计算A/B。当中A是不超过1000位的正整数，B是1位正整数。你须要输出商数Q和余数R，使得A = B * Q + R成立。

输入格式：

输入在1行中依次给出A和B。中间以1空格分隔。

输出格式：

在1行中依次输出Q和R，中间以1空格分隔。

输入例子：

123456789050987654321 7

输出例子：

17636684150141093474 3

import java.util.Scanner;

/**
 * @author jwang1 Success Factors
 */

public class Main {
  public static void main(String[] args) {

    String a;
    StringBuffer q_res = new StringBuffer();
    int b, r, q;
    Scanner cin = new Scanner(System.in);
    a = cin.next();
    b = cin.nextInt();
    int len = a.length();
    int curr = a.charAt(0) - ‘0‘;
    if (curr >= b) {
      q_res.append(curr / b);
    }
    for (int i = 1; i < len; i++) {
      q = curr % b;
      curr = q * 10 + a.charAt(i) - ‘0‘;
      q_res.append(curr / b);
    }
    q = curr % b;
    r = q;
    if (len == 1 && a.charAt(0) - ‘0‘ < b) {
      System.out.print("0 " + (a.charAt(0) - ‘0‘));
    } else {
      System.out.print(q_res + " " + r);
    }
  }
}

//用JAVA做比較简单
import java.math.BigInteger;
import java.util.Scanner;


public class Main {
    public static void main(String[] args) {
        Scanner cin = new Scanner(System.in);
        BigInteger a = cin.nextBigInteger();
        BigInteger b = cin.nextBigInteger();
        
        BigInteger q = a.divide(b);
        BigInteger r = a.mod(b);
        System.out.println(q+" "+r);
    }
}