os.path.join()

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os.path.join()
函数功能:连接两个或更多的路径名组件

如果各组件名首字母不包含’/’,则函数会自动加上

如果有一个组件是一个绝对路径,则在它之前的所有组件均会被舍弃

如果最后一个组件为空,则生成的路径以一个’/’分隔符结尾

Demo1

import os

Path1 = home
Path2 = develop
Path3 = code

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print (Path10 = ,Path10)
print (Path20 = ,Path20) 

 

输出如下:

Path10 =  homedevelopcode
Path20 =  homedevelopcode

Demo2

import os

Path1 = /home
Path2 = develop
Path3 = code

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print (Path10 = ,Path10)
print (Path20 = ,Path20) 

 

输出如下:

Path10 =  /homedevelopcode
Path20 =  /homedevelopcode

 

Demo3

import os

Path1 = home
Path2 = /develop
Path3 = code

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print (Path10 = ,Path10)
print (Path20 = ,Path20) 

 

输出如下:

Path10 =  home/developcode
Path20 =  /developcode

 

Demo4

import os

Path1 = home
Path2 = develop
Path3 = /code

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print (Path10 = ,Path10)
print (Path20 = ,Path20) 

 

输出如下:

Path10 =  homedevelop/code
Path20 =  /code

 

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