CF #541 D Gourmet choice
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link:https://codeforces.com/contest/1131
题意:
给定一些大小比较,输出排名。
思路:
这道题我用的是拓扑排序,又因为有等于号的存在,我用了并查集。
结束后这道题惨遭fst,因为我拓扑排序本应只放入一个集合的代表点,但是我放入了多次。
#include <algorithm> #include <iterator> #include <iostream> #include <cstring> #include <cstdlib> #include <iomanip> #include <bitset> #include <cctype> #include <cstdio> #include <string> #include <vector> #include <stack> #include <cmath> #include <queue> #include <list> #include <map> #include <set> #include <cassert> /* ⊂_ヽ \\ Λ_Λ 来了老弟 \(‘?‘) > ⌒ヽ / へ\ / / \\ ? ノ ヽ_つ / / / /| ( (ヽ | |、\ | 丿 \ ⌒) | | ) / ‘ノ ) L? */ using namespace std; #define lson (l , mid , rt << 1) #define rson (mid + 1 , r , rt << 1 | 1) #define debug(x) cerr << #x << " = " << x << " "; #define pb push_back #define pq priority_queue typedef long long ll; typedef long double ld; typedef unsigned long long ull; //typedef __int128 bll; typedef pair<ll ,ll > pll; typedef pair<int ,int > pii; typedef pair<int,pii> p3; //priority_queue<int> q;//这是一个大根堆q //priority_queue<int,vector<int>,greater<int> >q;//这是一个小根堆q #define fi first #define se second //#define endl ‘ ‘ #define boost ios::sync_with_stdio(false);cin.tie(0) #define rep(a, b, c) for(int a = (b); a <= (c); ++ a) #define max3(a,b,c) max(max(a,b), c); #define min3(a,b,c) min(min(a,b), c); const ll oo = 1ll<<17; const ll mos = 0x7FFFFFFF; //2147483647 const ll nmos = 0x80000000; //-2147483648 const int inf = 0x3f3f3f3f; const ll inff = 0x3f3f3f3f3f3f3f3f; //18 const int mod = 1e8; const double esp = 1e-8; const double PI=acos(-1.0); const double PHI=0.61803399; //黄金分割点 const double tPHI=0.38196601; template<typename T> inline T read(T&x){ x=0;int f=0;char ch=getchar(); while (ch<‘0‘||ch>‘9‘) f|=(ch==‘-‘),ch=getchar(); while (ch>=‘0‘&&ch<=‘9‘) x=x*10+ch-‘0‘,ch=getchar(); return x=f?-x:x; } inline void cmax(int &x,int y){if(x<y)x=y;} inline void cmax(ll &x,ll y){if(x<y)x=y;} inline void cmin(int &x,int y){if(x>y)x=y;} inline void cmin(ll &x,ll y){if(x>y)x=y;} /*-----------------------showtime----------------------*/ const int maxn = 1e3+9; char mp[maxn][maxn]; int fa[maxn*2]; int find(int x){ if(fa[x] == x) return x; return fa[x] = find(fa[x]); } void uni(int x,int y){ int fx = find(x); int fy = find(y); if(fx == fy) return ; fa[fx] = fy; } int ans[maxn*2],tmp[maxn*2]; int du[maxn*2],vis[maxn*2]; vector<int>G[maxn*2]; int main(){ int n,m; scanf("%d%d", &n, &m); rep(i, 1, n) scanf("%s", mp[i] + 1); rep(i, 1, n+m) fa[i] = i; rep(i, 1, n) { rep(j, 1, m) { if(mp[i][j] == ‘=‘) uni(i, j+n); } } rep(i, 1, n) { rep(j, 1, m) { if(mp[i][j] == ‘=‘) continue; int u = find(i), v = find(j+n); if(mp[i][j] == ‘>‘){ du[u]++; G[v].pb(u); } else { du[v]++; G[u].pb(v); } } } queue<pii>que; for(int i=1; i<=n+m; i++){ if(du[find(i)] == 0 && vis[find(i)] == 0) { que.push(pii(find(i),1)),vis[find(i)] = 1,tmp[find(i)] = 1; } } while(!que.empty()){ int u = que.front().fi;int s = que.front().se; que.pop(); for(int i=0; i<G[u].size(); i++){ int v = G[u][i]; du[v] --; if(du[v] ==0 && vis[v] == 0) { tmp[v] = s+1; que.push(pii(v, s+1)); vis[v] = 1; } } } int flag = 1; for(int i=1; i<=n+m; i++) if(vis[find(i)] == 0) flag = 0; if(flag == 0) puts("No"); else { puts("Yes"); for(int i=1; i<=n; i++) printf("%d ", tmp[find(i)]); puts(""); for(int i=1; i<=m; i++) printf("%d ", tmp[find(i+n)]); puts(""); } return 0; }
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