PAT 甲级 A1070 (2019/02/19)
Posted zjsaipplp
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了PAT 甲级 A1070 (2019/02/19)相关的知识,希望对你有一定的参考价值。
#include<cstdio>
#include<algorithm>
using namespace std;
struct Mooncake{
double inventory; //库存
double total_value; //总价
double unit_price; //单价
}cake[1001];
bool cmp(Mooncake a, Mooncake b){
return a.unit_price > b.unit_price; //按照单价从高到低
}
int main(){
int N, D;
scanf("%d %d", &N, &D);
for(int i = 0; i < N; i++){
scanf("%lf", &cake[i].inventory);
}
for(int i = 0; i < N; i++){
scanf("%lf", &cake[i].total_value);
cake[i].unit_price = cake[i].total_value / cake[i].inventory; //计算单价
}
sort(cake, cake + N, cmp); //排序
double total_cost = 0.0;
for(int i = 0; i < N; i++){
if(D > cake[i].inventory){ //需求大于库存
D -= cake[i].inventory; //第i种月饼全部卖出
total_cost += cake[i].total_value; //这些月饼的总价算进花费
}else{ //需求小于库存
total_cost += cake[i].unit_price * D; //只卖出剩余需求量的月饼
break;
}
}
printf("%.2f", total_cost);
return 0;
}
以上是关于PAT 甲级 A1070 (2019/02/19)的主要内容,如果未能解决你的问题,请参考以下文章