复制某文件夹及其子文件夹中的一定大小的文件

Posted 2021-02-09 xiaodebing

# coding=utf-8
import os
import shutil
import os.path

def get_size(path_in,path_out):
    fileList = os.listdir(path_in)  # 获取path目录下所有文件
    for filename in fileList:
        pathTmp = os.path.join(path_in,filename)  # 获取path与filename组合后的路径
        if os.path.isdir(pathTmp):   # 判断是否为目录
            get_size(pathTmp,path_out)        # 是目录就继续递归查找
        elif os.path.isfile(pathTmp):  # 判断是否为文件
            filesize = os.path.getsize(pathTmp)  # 如果是文件，则获取相应文件的大小
            print(‘目录中的子文件大小：%d字节‘ % filesize)
            if filesize > 10240:
                if pathTmp.endswith(‘gif‘):
                    shutil.copyfile(pathTmp, os.path.join(path_out, filename))
                else :
                    shutil.copyfile(pathTmp, os.path.join(path_out,filename) + ‘.gif‘)
#path= input("输入路径：").strip()  #由用户指定文件路径
path_in = ‘C:\Users\xxx\Desktop\img‘
path_out = ‘d:\img‘
get_size(path_in,path_out)

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