scrapy meta不用pipe用命令-o

Posted 2021-02-08 cxhzy

1.　　spider代码:

# -*- coding: utf-8 -*-
import scrapy
from tencent1.items import Tencent1Item
import json
class Mytest1Spider(scrapy.Spider):
    name = ‘tc1‘
    start_urls = [‘https://hr.tencent.com/position.php?lid=&tid=&keywords=python&start=0#a/‘]

    def parse(self, response):
        item = Tencent1Item()
        tr = response.xpath("//tr[@class=‘even‘]|//tr[@class=‘odd‘]")
        for i in tr:
            item[‘job_name‘]=i.xpath(‘./td[1]/a/text()‘).extract_first()
            item[‘job_type‘] = i.xpath(‘./td[2]/text()‘).extract_first()
            item[‘job_num‘] = i.xpath(‘./td[3]/text()‘).extract_first()
            item[‘job_place‘] = i.xpath(‘./td[4]/text()‘).extract_first()
            item[‘job_time‘] = i.xpath(‘./td[5]/text()‘).extract_first()
            # print(item)
            url1 = i.xpath(‘./td[1]/a/@href‘).extract_first()
            url1 = ‘https://hr.tencent.com/{}‘.format(url1)
            yield scrapy.Request(url=url1,meta={‘job_item‘:item},callback=self.parse_detail)
        # #下一页网址
        # url_next = response.xpath(‘//a[@id = "next"]/@href‘).extract_first()
        # if ‘50‘in url_next:
        #     return
        # url_next = ‘https://hr.tencent.com/{}‘.format(url_next)
        # print(url_next)
        # yield scrapy.Request(url_next)

    def parse_detail(self,response):
        item = response.meta[‘job_item‘]
        data = response.xpath(‘//ul[@class="squareli"]/li/text()‘).extract()
        item[‘job_detail‘] = ‘
‘.join(data)
        return item

2.　　items代码:

import scrapy


class Tencent1Item(scrapy.Item):
    # define the fields for your item here like:
    # name = scrapy.Field()
    job_name = scrapy.Field()
    job_type = scrapy.Field()
    job_num = scrapy.Field()
    job_place = scrapy.Field()
    job_time = scrapy.Field()
    job_detail = scrapy.Field()

3.　　命令,(job.jl 是文件名字)