UVALive 7512 November 11th 题解
Posted kirinsb
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思路:心态大崩,最多不讲了,最少应该是三个一组,比如......应该是.S..S.,这样占的最多
代码:
#include<set> #include<map> #include<cmath> #include<queue> #include<string> #include<cstdio> #include<cstring> #include<sstream> #include<algorithm> typedef long long ll; using namespace std; const int maxn = 1000 + 10; const int MOD = 1e9 + 7; const int INF = 0x3f3f3f3f; int row[maxn][maxn], cnt[maxn]; int getMax(int s){ return (s + 1) / 2; } int getMin(int s){ if(s % 3 == 0){ return s / 3; } else if(s % 3 == 1){ return (s + 2) / 3; } else return (s + 1) / 3; } int main(){ int t, ca = 1; scanf("%d", &t); while(t--){ int b, r, s; scanf("%d%d", &r, &s); scanf("%d", &b); memset(cnt, 0 ,sizeof(cnt)); for(int i = 1; i <= b; i++){ int x, y; scanf("%d%d", &x, &y); row[x][cnt[x]++] = y; } int Max = 0, Min = 0; for(int i = 0; i < r; i++){ if(cnt[i] == 0){ Max += getMax(s); Min += getMin(s); } else{ sort(row[i], row[i] + cnt[i]); for(int j = 0; j < cnt[i]; j++){ if(j == 0){ int tmp = row[i][j] - 0; Max += getMax(tmp); Min += getMin(tmp); } else{ int tmp = row[i][j] - row[i][j - 1] - 1; Max += getMax(tmp); Min += getMin(tmp); } } int tmp = s - 1 - row[i][cnt[i] - 1]; Max += getMax(tmp); Min += getMin(tmp); } } printf("Case #%d: %d %d ", ca++, Max, Min); } return 0; } /* 3 2 3 1 0 1 2 3 0 1 1 1 0 0 */
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