1115 Counting Nodes in a BST (30 分)建立二叉搜索树,求每层结点数目
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A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than or equal to the node‘s key.
- The right subtree of a node contains only nodes with keys greater than the node‘s key.
- Both the left and right subtrees must also be binary search trees.
Insert a sequence of numbers into an initially empty binary search tree. Then you are supposed to count the total number of nodes in the lowest 2 levels of the resulting tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤1000) which is the size of the input sequence. Then given in the next line are the N integers in [?10001000] which are supposed to be inserted into an initially empty binary search tree.
Output Specification:
For each case, print in one line the numbers of nodes in the lowest 2 levels of the resulting tree in the format:
n1 + n2 = n
where n1
is the number of nodes in the lowest level, n2
is that of the level above, and n
is the sum.
Sample Input:
9
25 30 42 16 20 20 35 -5 28
Sample Output:
2 + 4 = 6
思路:
通过先序遍历建立二叉树,然后使用先序遍历求每层结点数。
#include<iostream> #include<vector> #include<algorithm> #include<queue> #include<string> #include<map> #include<set> #include<stack> using namespace std; struct Node { int data; Node *lchild,*rchild; }; void insertBST(Node *&root,int key) { if(root==nullptr) { root=new Node; root->data=key; root->lchild=root->rchild=nullptr; return; } if(key>root->data) insertBST(root->rchild,key); else insertBST(root->lchild,key); } int level[1001]; int maxLevel=0; void dfs(int depth,Node *root) { if(root==nullptr) return; level[depth]++; maxLevel=max(depth,maxLevel); dfs(depth+1,root->lchild); dfs(depth+1,root->rchild); } int main() { int n; cin>>n; //int a[n+1]; Node *root=nullptr; for(int i=0;i<n;i++) { int temp; cin>>temp; insertBST(root,temp); } dfs(1,root); // for(int i=1;i<=maxLevel;i++) // cout<<level[i]<<" "; // cout<<endl; cout<<level[maxLevel]<<" + "<<level[maxLevel-1]<<" = "<<level[maxLevel]+level[maxLevel-1]; return 0; }
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