operator, itertools

Posted 2021-02-04 amber-liu

import operator

import itertools

info_list = [
    {‘name‘: ‘Quinn‘, ‘age‘: 50},
    {‘name‘: ‘Ryan‘, ‘age‘: 18},
    {‘name‘: ‘May‘, ‘age‘: 30}
]

new_list = sorted(info_list, key=operator.itemgetter(‘age‘))
print(new_list)
# 同理, 如果对属性排序, 可以用sorted(obj_list, operator.attrgetter(‘attribute‘))
# [{‘name‘: ‘Ryan‘, ‘age‘: 18}, {‘name‘: ‘May‘, ‘age‘: 30}, {‘name‘: ‘Quinn‘, ‘age‘: 50}]


a = [1, 5, 9, 2]
b = [7, 77, 5, 8]
print(itertools.chain(a, b))  # <itertools.chain object at 0x00000088F43454E0>
print(list(itertools.chain(a, b)))  # [1, 5, 9, 2, 7, 77, 5, 8]


# 重复操作的判断问题

# 可以利用redis.setnx 返回结果(True, False) 来加锁, 如果为False ,则证明当前已操作(已经设置过值了,但是需要时间), 提示勿重复操作