771. Jewels and Stones - Easy
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You‘re given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
are letters. Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S
andJ
will consist of letters and have length at most 50.- The characters in
J
are distinct.
time: O(M+N), space: O(M) -- M: # of length of J
class Solution { public int numJewelsInStones(String J, String S) { Set<Character> set = new HashSet<>(); for(char c : J.toCharArray()) { set.add(c); } int cnt = 0; for(char c : S.toCharArray()) { if(set.contains(c)) { cnt++; } } return cnt; } }
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LeetCode 771. Jewels and Stones
[leetcode-771-Jewels and Stones]