XML与Object之间的互转

Posted 2021-01-24

private static final String W3C_XML_SCHEMA_NS_URI = "http://www.w3.org/2001/XMLSchema";

/**

• 将对象转换成xml
• @param obj 要转成xml的对象
• @param xsdPath 标准的xml文件就传null

• @return xml格式的字符串
  */
  public static String objToXml(Object obj, String xsdPath) throws JAXBException, SAXException {
  StringWriter sw = new StringWriter();
  JAXBContext jAXBContext;
  jAXBContext = JAXBContext.newInstance(obj.getClass());
  Marshaller marshaller = jAXBContext.createMarshaller();
  marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
  marshaller.setProperty(Marshaller.JAXB_ENCODING, "GBK"); // 防止文件中文乱码
  if (TextUtils.isNotEmpty(xsdPath)) {
  marshaller.setSchema(SchemaFactory.newInstance(W3C_XML_SCHEMA_NS_URI).newSchema(new File(xsdPath)));
  }
  marshaller.marshal(obj, sw);
  return sw.toString();
  }

  /**

• 将xml格式转换为对象.
• @param xml xml字符串
• @param clazz 要转换成的对象
• @param xsdPath 标准的xml解析传null
• @return 转换后的对象br/>*/
  @SuppressWarnings("unchecked")
  public static <T> T xmlToObj(String xml, Class<T> clazz, String xsdPath) throws JAXBException, SAXException {
  JAXBContext jAXBContext = JAXBContext.newInstance(clazz);
  Unmarshaller um = jAXBContext.createUnmarshaller();
  if (TextUtils.isNotEmpty(xsdPath)) {
  um.setSchema(SchemaFactory.newInstance(W3C_XML_SCHEMA_NS_URI).newSchema(new File(xsdPath)));
  }
  return (T) um.unmarshal(new StreamSource(new StringReader(xml)));
  }