uva213
Posted 033000-
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采用二进制存储编码
由于输入并不连续,所以采用getchar()读取
#include<iostream> #include<cmath> #include<cstdio> #include<cstdlib> #include<cstring> #include<iomanip> #include<assert.h> #include<ctime> #include<vector> #include<list> #include<map> #include<set> #include<sstream> #include<stack> #include<queue> #include<string> #include<bitset> #include<algorithm> using namespace std; #define me(s) memset(s,0,sizeof(s)) #define pf printf #define sf scanf #define Di(x) int x;scanf("%d",&x) #define in(x) inp(x) #define in2(x,y) inp(x),inp(y) #define in3(x,y,z) inp(x),inp(y),inp(z) #define ins(x) scanf("%s",x) #define ind(x) scanf("%lf",&x) #define IO ios_base::sync_with_stdio(0);cin.tie(0) #define READ freopen("C:/Users/ASUS/Desktop/in.txt","r",stdin) #define WRITE freopen("C:/Users/ASUS/Desktop/out.txt","w",stdout) template<class T> void inp(T &x) {//读入优化 char c = getchar(); x = 0; for (; (c < 48 || c>57); c = getchar()); for (; c > 47 && c < 58; c = getchar()) { x = (x << 1) + (x << 3) + c - 48; } } typedef pair <int, int> pii; typedef long long ll; typedef unsigned long long ull; const int inf = 0x3f3f3f3f; const int mod = 1e9 + 7; const double pi = acos(-1.0); const double eps = 1e-15; int read_char(){ for(;;){ char ch=getchar(); if(ch!=‘ ‘&&ch!=‘ ‘) return ch; } } int read_int(int len){ int v=0; while(len--){ v=v*2+read_char()-‘0‘; } return v; } int code[8][1<<8]; int read_codes(){ me(code); code[1][0]=read_char(); for(int len=2;len<8;len++){ for(int s=0;s<(1<<len)-1;s++){ char ch=getchar(); if(ch==EOF) return 0; if(ch==‘ ‘||ch==‘ ‘) return 1; code[len][s]=ch; } } } int main(){ // READ; //WRITE; while(read_codes()){ for(;;){ int len=read_int(3); if(len==0) break; for(;;){ int v=read_int(len); if(v==(1<<len)-1) break; putchar(code[len][v]); } } puts(""); } }
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