UVa-1600 Patrol Robot

Posted 2021-01-22 asurudo

 1 #include <bits/stdc++.h>
 2 
 3 using namespace std;
 4 
 5 struct Node
 6 {
 7     int r,c,g;
 8     Node(int r,int c,int g): r(r),c(c),g(g) {}
 9     Node() {}
10 };
11 
12 int m[22][22];
13 
14 int rt,ct;
15 int k;
16 void read()
17 {
18     memset(m,0,sizeof(m));
19     cin >> rt >> ct >> k;
20     for(int i = 0;i < rt;i ++)
21         for(int j = 0; j < ct;j ++)
22             cin >> m[i][j];
23 }
24 
25 const int dr[] = {1,0,0,-1};
26 const int dc[] = {0,1,-1,0};
27 
28 int d[22][22][22];
29 bool limit(Node v)
30 {
31     return v.r>=0&&v.r<rt&&v.c>=0&&v.c<ct&&v.g<=k;
32 }
33 int solve()
34 {
35     memset(d,-1,sizeof(d));
36     queue<Node> q;
37     q.push(Node(0,0,m[0][0]));
38     d[0][0][m[0][0]] = 0;
39     while(!q.empty())
40     {
41         Node u = q.front();q.pop();
42         if(u.r==rt-1&&u.c==ct-1)    return d[u.r][u.c][u.g];
43         for(int i = 0; i < 4;i ++)
44         {
45             Node v = u;v.r += dr[i];v.c += dc[i];
46             if(limit(v)&&m[v.r][v.c]==0)    v.g = 0;
47             if(limit(v)&&m[v.r][v.c]==1)    v.g ++;
48             if(limit(v)&&d[v.r][v.c][v.g]<0)
49             {
50                 d[v.r][v.c][v.g] = d[u.r][u.c][u.g] + 1;
51                 q.push(v);
52             }
53         }
54     }
55     return -1;
56 }
57 
58 void print(int rnt)
59 {
60     cout << rnt << endl;
61 }
62 int main()
63 {
64     int T;
65     cin >> T;
66     while(T --)
67     {
68         read();
69         int rnt = solve();
70         print(rnt);
71     }
72     return 0;
73 }