瞎jb操作

Posted 2021-01-18 cerutodog

import re
def test(teststr, *args):
    #strformatter = "%s"
    myargs = args[0]
    if len(args) > 1:
        for i in args[1:]:
            myargs += ‘|‘ + str(i)
            #strformatter += "|%s"
    #regex = """ + strformatter + """ + " % " + "(" + myargs + ")"
    regex = "myargs"
    print(regex)

    #print(re.findall(regex, teststr))
    print(re.findall(regex, s))


s = "chinese,translated,censored,nanao,sole_male,beauty_mark,blowjob,kimono,milf,sole_female,td_full_color"
#t1 = re.compile(‘milf‘, re.S)
regex = "%s|%s|%s" % (‘chinese‘, ‘milf‘, ‘sdfjsdfsdf‘)
print(regex)
print(len(re.findall(regex, s)))
#test(s, "chinese", "milf")

import re


def test(teststr, *args):
    length = len(args)
    regex = args[0]
    if len(args) > 1:
        for i in args[1:]:
            regex += ‘|‘ + str(i)
    print(regex)
    print(re.findall(regex, teststr))
    if len(re.findall(regex, teststr)) == length:
        print("ok")



s = "chinese,translated,censored,nanao,sole_male,beauty_mark,blowjob,kimono,milf,sole_female,td_full_color"
test(s, "chinese", "milf", "nanao")

import re



def test(teststr, *args):
    length = len(args)
    regex = args[0]
    if len(args) > 1:
        for i in args[1:]:
            regex += ‘|‘ + str(i)
    print(regex)
    print(re.findall(regex, teststr))
    re2 = re.findall(regex, teststr)
    print(re2)
    re2 = sorted(set(re2), key=re2.index)
    print(re2)
    if len(re2) == length:
        list2.append(num)



s = "english,dragon_ball_z,cell,bisexual,blowjob,insect_boy,selfcest,anal,beauty_mark,blood,blowjob,cunnilingus,dark_skin,double_blowjob,double_penetration,piercing,sole_female,td_full_color,td_group,td_mmf_threesome"
test2 = "chinese,milf,blowjob"
test5 = test2.split(",")
print(test5)
test(s, *test5)
#test(s, "chinese", "milf", "nanao")