482. License Key Formatting
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https://leetcode.com/problems/license-key-formatting/discuss/96528/Easy-to-understand-using-StringBuilder class Solution { public String licenseKeyFormatting(String S, int K) { String s1 = S.replace("-", ""); s1 = s1.toUpperCase(); StringBuilder sb = new StringBuilder(); for(int i = 0; i < s1.length(); i++){ sb.append(s1.charAt(i)); } int len = sb.length(); // inserting "-" from back at every k position for(int i = K; i < len; i = i + K){ sb.insert(len - i, ‘-‘); } return sb.toString(); } } // "5F3Z-2e-9-w", K = 4 // "5F3Z2E9W" // "5F3Z-2E9W"
You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes.
Given a number K, we would want to reformat the strings such that each group contains exactly K characters, except for the first group which could be shorter than K, but still must contain at least one character. Furthermore, there must be a dash inserted between two groups and all lowercase letters should be converted to uppercase.
Given a non-empty string S and a number K, format the string according to the rules described above.
Example 1:
Input: S = "5F3Z-2e-9-w", K = 4 Output: "5F3Z-2E9W" Explanation: The string S has been split into two parts, each part has 4 characters. Note that the two extra dashes are not needed and can be removed.
Example 2:
Input: S = "2-5g-3-J", K = 2 Output: "2-5G-3J" Explanation: The string S has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.
Note:
- The length of string S will not exceed 12,000, and K is a positive integer.
- String S consists only of alphanumerical characters (a-z and/or A-Z and/or 0-9) and dashes(-).
- String S is non-empty.
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