85. Maximal Rectangle
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Given a 2D binary matrix filled with 0‘s and 1‘s, find the largest rectangle containing only 1‘s and return its area. Example: Input: [ ["1","0","1","0","0"], ["1","0","1","1","1"], ["1","1","1","1","1"], ["1","0","0","1","0"] ] Output: 6 https://www.youtube.com/watch?v=2Yk3Avrzauk&t=450s class Solution { public int maximalRectangle(char[][] matrix) { if(matrix == null || matrix.length == 0 || matrix[0].length == 0) return 0; int row = matrix.length; int col = matrix[0].length; int[] height = new int[col]; int max = 0; for(int i = 0; i < row; i++){ for(int j = 0; j < col; j++){ if(matrix[i][j] == ‘1‘){ height[j]++; }else{ height[j] = 0; } } int area = largestArea(height); max = Math.max(area, max); } return max; } private int largestArea(int[] height){ int len = height.length; Stack<Integer> s = new Stack<Integer>(); int maxArea = 0; for(int i = 0; i <= len; i++){ int h = (i == len ? 0 : height[i]); if(s.isEmpty() || h >= height[s.peek()]){ s.push(i); }else{ int tp = s.pop(); maxArea = Math.max(maxArea, height[tp] * (s.isEmpty() ? i : i - 1 - s.peek())); i--; } } return maxArea; } }
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