清北最后冲刺 张浩威 吃鱼

Posted 2021-01-17 lcan

为什么要考虑每个时刻呢，考虑每条鱼什么时候被吃不就行了吗，至于时刻相同编号大小的问题，用pair不就可以吗

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 pair<int,int> a[200005],p;
 4 int NOW,i,n,m,x,now;
 5 int cmp(pair<int,int> i,pair<int,int> j) {return i.first>j.first || i.first==j.first && i.second>j.second;}
 6 int main()
 7 {
 8     freopen("fish.in","r",stdin);
 9     freopen("fish.out","w",stdout);
10     while (cin>>m)
11     {
12         cin>>n>>x;
13         NOW=0; now=0;
14         for (i=1; i<=n; i++)
15         {
16             scanf("%d",&a[i].second);
17             a[i].first=a[i].second;
18             push_heap(a+1,a+i+1,cmp);
19             if (i<=m) now++;
20         }
21         for (i=1; i<=m; i++)
22         {
23             if (!now) break;
24             if (a[1].first>x) break;
25             p = a[1];
26             pop_heap(a+1,a+now+1,cmp);
27             NOW++; now--;
28             if (p.first<x && now+NOW<m)
29             {
30                 now++;
31                 a[now]=p; a[now].first+=a[now].second;
32                 push_heap(a+1,a+now+1,cmp);
33             }
34         }
35         cout<<m-now-NOW<<‘ ‘<<now<<endl;
36     }
37     return 0;
38 }