三级菜单

Posted 2021-01-15 python884

三级菜单

date = {
    ‘北京‘: {
        ‘海淀‘: {
            ‘五道口‘: {
                ‘sogo‘: {},
                ‘网易‘: {},
                ‘google‘: {
                    ‘美女‘: ‘小姐‘,
                    ‘帅哥‘: ‘鸭子‘
                }
            },
            ‘中关村‘: {
                ‘爱奇艺‘: {},
                ‘汽车之家‘: {},
                ‘youku‘: {},
            },
            ‘上地‘: {
                ‘百度‘: {},
            },
        },
        ‘昌平‘: {
            ‘沙河‘: {
                ‘汇德商厦老男孩‘: {},
                ‘北航‘: {},
            },
            ‘天通苑‘: {},
            ‘回龙观‘: {},
        },
        ‘朝阳‘: {
            ‘朝阳大妈‘: {}
        },
        ‘东城‘: {},
    },
    ‘上海‘: {
        ‘闵行‘: {
            "人民广场": {
                ‘炸鸡店‘: {‘在人民广场吃炸鸡‘: {}}
            }
        },
        ‘闸北‘: {
            ‘火车战‘: {
                ‘携程‘: {}
            }
        },
        ‘浦东‘: {},
    },
    ‘山东‘: {
        ‘高丽‘: {}
    },}

Flag = True
while Flag:
    for key in date:
        print(key)
    nun = input(‘请输入城市‘)
    if nun == ‘q‘:
        Flag = False
    if nun == ‘b‘:
        break
    if nun in date:
        while Flag:
            for i in date[nun]:
                print(i)
            nun1 = input(‘请输入‘)

            if nun1 == ‘b‘:
                break
            if nun1 in date[nun]:
                while Flag:
                    for i1 in date[nun][nun1]:
                        print(i1)
                    nun2 = input(‘请输入‘)

                    if nun2 == ‘b‘:
                        break
                    if nun2 in date[nun][nun1]:
                        while Flag:
                            for i2 in date[nun][nun1][nun2]:
                                print(i2)
                            nun3 = input(‘请输入‘)

                            if nun3 == ‘b‘:
                                break
                            if nun3 in date[nun][nun1][nun2]:
                                while Flag:
                                    for i3 in date[nun][nun1][nun2][nun3]:
                                        print(nun3)
                                    nun4 = input(‘最后一行了，输入b，直接结束‘)

                                    if nun4 == ‘b‘:
                                        break

三级菜单，优化版
****************************************************
Flag = True
nun = date
li = []
while Flag:
    for key in nun:
        print(key)
    in_put = input(‘请输入‘)
    if in_put in nun:
        li.append(nun)
        nun = nun[in_put]
    if in_put == ‘q‘:
        li.pop()
        Flag = False
    if in_put == ‘b‘:
        break