ROADS POJ - 1724(分层最短路)
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就是在最短路的基础上 多加了一个时间的限制 , 多一个限制多一维就好了 记住 分层最短路要用dijistra !!!
#include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <cctype> #include <set> #include <vector> #include <stack> #include <queue> #include <algorithm> #include <cmath> #include <bitset> #define rap(i, a, n) for(int i=a; i<=n; i++) #define rep(i, a, n) for(int i=a; i<n; i++) #define lap(i, a, n) for(int i=n; i>=a; i--) #define lep(i, a, n) for(int i=n; i>a; i--) #define rd(a) scanf("%d", &a) #define rlld(a) scanf("%lld", &a) #define rc(a) scanf("%c", &a) #define rs(a) scanf("%s", a) #define pd(a) printf("%d ", a); #define plld(a) printf("%lld ", a); #define pc(a) printf("%c ", a); #define ps(a) printf("%s ", a); #define MOD 2018 #define LL long long #define ULL unsigned long long #define Pair pair<int, int> #define mem(a, b) memset(a, b, sizeof(a)) #define _ ios_base::sync_with_stdio(0),cin.tie(0) //freopen("1.txt", "r", stdin); using namespace std; const int maxn = 10010, INF = 0x7fffffff, LL_INF = 0x7fffffffffffffff; int k, n, m; int dis[maxn][110], vis[maxn][110], head[maxn]; int cnt; struct edge { int u, v, d, t; edge(int u, int v, int d, int t) : u(u), v(v), d(d), t(t) {} }; vector<edge> Edge; vector<int> G[maxn << 1]; struct node { int u, d, t; node(int u, int d, int t) : u(u), d(d), t(t) {} bool operator < (const node &a) const { return d > a.d; } }; void add(int u, int v, int d, int t) { Edge.push_back(edge(u, v, d, t)); G[u].push_back(Edge.size() - 1); } void dijkstra() { priority_queue<node> Q; for(int i = 0; i < maxn; i++) for(int j = 0; j < 110; j++) dis[i][j] = INF; mem(vis, 0); Q.push(node(1, 0, 0)); dis[0][1] = 0; // vis[0][1] = 1; while(!Q.empty()) { node x = Q.top(); Q.pop(); int u = x.u; int t = x.t; if(vis[t][u]) continue; vis[t][u] = 1; for(int i = 0; i < G[u].size(); i++) { edge e = Edge[G[u][i]]; if(dis[t + e.t][e.v] > dis[t][u] + e.d && t + e.t <= k) { dis[t + e.t][e.v] = dis[t][u] + e.d; Q.push(node(e.v, dis[t + e.t][e.v], t + e.t)); } } } } int main() { int u, v, d, t; rd(k), rd(n), rd(m); for(int i = 1; i <= m; i++) { rd(u), rd(v), rd(d), rd(t); add(u, v, d, t); } dijkstra(); int maxx = INF; for(int i = 0; i <= k; i++) maxx = min(maxx, dis[i][n]); if(maxx == INF) return puts("-1"), 0; cout << maxx << endl; return 0; }
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