批处理:根据进程名称查询进程，如果有进程就输出up没有就输出donw

Posted 2021-01-12 chenglee

需求:windows系统上  根据进程名称查询进程，如果有进程就输出 up ，没有就输出  donw.

::Final interpretation is owned by chenglee
::@echo off<nul 3>nul
@echo off&title Checking For SystemProcess, Thankyou...
:2
color 0E
wmic process get name | findStr /i "chat*"
::if not "%%a"=="%num%" goto en1
IF ERRORLEVEL 1 goto 1
IF ERRORLEVEL 0 goto 0
   
:0
echo.UP!!
echo.Process exists, Exit after 5 seconds...
::进程存在,5秒后退出,如果不想退出的话,删掉下面的exit, 加上goto 2.
choice /t 5 /d y /n >nul
exit
   
:1
echo.DOWN!!
echo.Process does not Exist, 5 Seconds later, Continue to judge...
::进程不存在,5秒后继续判断.
choice /t 5 /d y /n >nul
goto 2
pause
exit

　　

完成!!