#001# 归并排序
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js代码:
class MergeSort { // merge two sorted sequences: arr[start:mid] and arr[mid:end] static merge(arr, start, mid, end) { let leftArr = arr.slice(start, mid); // arr[mid] is excluded let rightArr = arr.slice(mid, end); // arr[end] is excluded // put on the buttom of each pile a sentinel // card, which contains a special value that // we use to simplify our codes let sentinel = Infinity; leftArr.push(sentinel); rightArr.push(sentinel); let i = 0, j = 0; // index of leftArr and rightArr for (let k = start; k < end; ++k) { arr[k] = leftArr[i] < rightArr[j] ? leftArr[i++] : rightArr[j++]; } } // sort arr[start:end], arr[end] is excluded static sort(arr, start, end) { // calling sort(arr, 0, 1) doesn‘t make // sense for there‘s only one element, // so just stop dividing/recursive and merge directly. if (start + 1 < end) { // divide the problem into two subproblems let mid = Math.floor((start + end) / 2); // recursively solve subproblems MergeSort.sort(arr, start, mid); MergeSort.sort(arr, mid, end); // combine the solutions to the subproblems into // the solution for the original problem. MergeSort.merge(arr, start, mid, end); } } static run(data) { // convert a string to a numeric array data = CommonUtil.handleData(data); MergeSort.sort(data, 0, data.length); console.log(data); } }
Python代码:
def merge(arr, start, mid, end): left = arr[start:mid] right = arr[mid:end] sentinel = float(‘inf‘) left.append(sentinel) right.append(sentinel) i = j = 0 for k in range(start, end): if left[i] < right[j]: arr[k] = left[i] i += 1 else: arr[k] = right[j] j += 1 def sort(arr, start, end): if start + 1 < end: mid = int((start + end) / 2) sort(arr, start, mid) sort(arr, mid, end) merge(arr, start, mid, end) arr = [1, 3, 5, 2, 12, 3, 22, 88, 23] sort(arr, 0, len(arr)) print(arr)
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