error: cast from ‘char*’ to ‘int’ loses precision
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程序:
char* addrCom;
addrCom= ......//赋值
if(-1 == (int)addrCom) //导致编译出错
{ ...... }
编译时出现错误:
error: cast from ‘char*’ to ‘int’ loses precision
因为我编译的系统为linux64位,其指针类型和long型大小相等(8B)而与int型4B,故会出现:loses precision。故:先将char*-->long,然后从long到int自动隐式转换。
将(int)addrCom 改为(long)addrCom
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