Swagger入参为List

Posted 2021-01-09 coisini

今天遇到一个奇葩的需求，为了方便，service的一个接口入参是List<Map>

repayMoney（List<Map<String,Object>）

那，我为了在controller调用service，入参类型得一致呀，

那么问题来了，controller入参也得是List吧，或者是其他形式的数据，转换为List<Map>

翻遍了整个项目，没看到之前有人swagger的controller里入参是List的，而且查了一下，

用@ApiImplicitParams注解的话，入参只能是String或者Integer，啊，这可怎么办，类似于这样

关注点在入参为List，这个测试写的不完善，大家只要关注入参就可以了

 

@ApiOperation(value = "测试")
    @RequestMapping(value = "/sanbiaoRepaymentAmount",method = RequestMethod.POST)
    @ApiImplicitParams({@ApiImplicitParam(name = "idCard", dataType = "String", value = "身份证号", paramType = "query", required = true),
            @ApiImplicitParam(name = "userNo", dataType = "Integer", value = "编号", paramType = "query", required = true),
            @ApiImplicitParam(name = "onePeriodAmount", dataType = "String", value = "金额", paramType = "query", required = true)})
    @ResponseBody
    public Result sanbiaoRepaymentAmount(@RequestParam(value = "idCard", required = true) String idCard,
                                         @RequestParam(value = "userNo", required = true) Integer userNo,
                                         @RequestParam(value = "onePeriodAmount", required = true) String onePeriodAmount) {
        Result result = new ResultSupport();
        List<Map<String,Object>> repayList = new ArrayList<Map<String,Object>>();
        Map paramMap = new HashMap();
        paramMap.put("idCard",idCard);
        paramMap.put("userNo",userNo);
        paramMap.put("onePeriodAmount",onePeriodAmount);
        repayList.add(paramMap);
        userService.repayMoney(repayList);
        return result;
    }

　　

 

好吧，查了一下，好像去掉ApiImplicitParams，就可以传list，

于是 我做了如下修改

 

@ApiOperation(value = "测试")
    @RequestMapping(value = "/sanbiaoRepaymentAmount",method = RequestMethod.POST)
    @ResponseBody
    public Result sanbiaoRepaymentAmount(@RequestParam(value = "idCardList", required = true) List<String> idCardList,
                                         @RequestParam(value = "userNoList", required = true) List<Integer> userNoList,
                                         @RequestParam(value = "onePeriodAmountList", required = true) List<String> onePeriodAmountList) {

        Result result = new ResultSupport();
        List<Map<String,Object>> repayList = new ArrayList<Map<String,Object>>();
        Map paramMap = new HashMap();
        for(int i=0; i<idCardList.size(); i++){
            //因为这里十分确定，三个入参list的长度是一致的，所以，在这里，把三个List对应的下标参数放在map里
            paramMap.put("idCard",userNoList.get(i));
            paramMap.put("userNo",onePeriodAmountList.get(i));
            paramMap.put("onePeriodAmount",onePeriodAmountList.get(i));
            repayList.add(paramMap);
        }
        System.out.println("haha");
        System.out.println(repayList);
　　　　 System.out.println(repayList.getClass());
        userService.repayMoney(repayList);
        return result;
    }

　　

 

开始测试--Swagger入参是这样得，看吧，DataType 是Array，数组呗

逗号分隔参数，就可以咯

顺利经过测试，能走到repayMoney()