HDU 1097 快速幂

Posted 2021-01-05 hadesblog

#include<iostream>

using namespace std;

long long quick(long long a,long long b,int c)
{
    int ans=1;
    a=a%c;
    while(b!=0)
    {
        if(b&1) ans=(ans*a)%c;
        b>>=1;
        a=(a*a)%c;
    }
    return ans;
}

int main()
{
    long long a,b;
    while(cin>>a>>b)
    {
        cout<<quick(a,b,10)<<endl;
    }
    return 0;
}