UVA-227 Puzzle(傻屌之王)

Posted asurudo

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了UVA-227 Puzzle(傻屌之王)相关的知识,希望对你有一定的参考价值。

  1 #include <iostream>
  2 #include <stdlib.h>
  3 #include <string>
  4 #include <vector>
  5 #include <algorithm>
  6 #include <string.h>
  7 #include <stack>
  8 #include <unordered_map>
  9 #include <math.h>
 10 #include <iomanip>
 11 
 12 using namespace std;
 13 
 14 int main()
 15 {
 16     char puzzleGraph[5][7];
 17     string inputLine;
 18     int cnt = 1;
 19     while(1)
 20     {
 21         int flag = 0,flag2 = 1;
 22         int cur_x,cur_y;
 23 
 24         for(int i = 0; i < 5; i ++)
 25         {
 26             if(flag2 && cnt!=1)
 27             {
 28                 getline(cin, inputLine);
 29                 i = -1;
 30                 flag2 = 0;
 31                 continue;
 32             }
 33             getline(cin, inputLine);
 34             if(i==0 && inputLine[0] == Z)
 35             {
 36                 flag = 1;
 37                 break;
 38             }
 39             for(int j = 0; j < 5; j ++)
 40             {
 41                 if(inputLine[j] ==  )
 42                 {
 43                     cur_x = i;
 44                     cur_y = j;
 45                     //    cout << "OK" << endl;
 46                 }
 47                 if(inputLine.size()==4 && j==3)
 48                 {
 49                     puzzleGraph[i][j] = inputLine[j++];
 50                 //    puzzleGraph[i][++j] = ‘ ‘;
 51                     cur_x = i;
 52                     cur_y = 4;
 53                     continue;
 54                 }
 55                 puzzleGraph[i][j] = inputLine[j];
 56             }
 57         }
 58 
 59         if(flag)
 60             break;
 61 
 62         string actions;
 63         cin >> actions;
 64         while(actions[actions.size()-1] != 0)
 65         {
 66             string tmp;
 67             cin >> tmp;
 68             actions += tmp;
 69         }
 70 
 71         for(int i = 0; actions[i]!=0; i ++)
 72         {
 73             //    cout << cur_x << " " << cur_y << endl;
 74             if(actions[i]==A)
 75             {
 76                 if(cur_x-1>=0)
 77                 {
 78                     puzzleGraph[cur_x][cur_y] = puzzleGraph[cur_x-1][cur_y];
 79                     cur_x --;
 80                 }
 81                 else
 82                 {
 83                     flag = 3;
 84                     break;
 85                 }
 86             }
 87             else if(actions[i]==B)
 88             {
 89                 if(cur_x+1<5)
 90                 {
 91                     puzzleGraph[cur_x][cur_y] = puzzleGraph[cur_x+1][cur_y];
 92                     cur_x ++;
 93                 }
 94                 else
 95                 {
 96                     flag = 3;
 97                     break;
 98                 }
 99             }
100             else if(actions[i]==R)
101             {
102                 if(cur_y+1<5)
103                 {
104                     puzzleGraph[cur_x][cur_y] = puzzleGraph[cur_x][cur_y+1];
105                     cur_y ++;
106                 }
107                 else
108                 {
109                     flag = 3;
110                     break;
111                 }
112             }
113             else if(actions[i]==L)
114             {
115                 if(cur_y-1>=0)
116                 {
117                     puzzleGraph[cur_x][cur_y] = puzzleGraph[cur_x][cur_y-1];
118                     cur_y --;
119                 }
120                 else
121                 {
122                     flag = 3;
123                     break;
124                 }
125             }
126         }
127         if(cnt!=1)
128             cout << endl;
129         cout << "Puzzle #" << cnt ++ << ":" << endl;
130         if(flag == 3)
131         {
132             cout << "This puzzle has no final configuration." << endl;
133             continue;
134         }
135 
136         puzzleGraph[cur_x][cur_y] =  ;
137 
138         for(int i = 0; i < 5; i ++)
139         {
140             for(int j = 0; j < 4; j ++)
141             {
142                 cout << puzzleGraph[i][j] << " ";
143             }
144             cout << puzzleGraph[i][4] << endl;
145         }
146     }
147     return 0;
148 }

 

以上是关于UVA-227 Puzzle(傻屌之王)的主要内容,如果未能解决你的问题,请参考以下文章

Puzzle UVa227(分析和问题解决)

uva 227 Puzzle (UVA - 227)

UVa - 227 - Puzzle

Uva 227-Puzzle 解题报告

习题3-5 Puzzle UVA - 227

Puzzle UVA - 227