获取文件路径文件名后缀名

Posted 2021-01-01 zhangdingqu

#########start 获取文件路径、文件名、后缀名############
from gevent import os

def jwkj_get_filePath_fileName_fileExt(filename):
    (filepath,tempfilename) = os.path.split(filename);
    (shotname,extension) = os.path.splitext(tempfilename);
    return filepath,shotname,extension
#########end 获取文件路径、文件名、后缀名############
print(jwkj_get_filePath_fileName_fileExt("D:/保存的图片/571711894929.png"))

 输出结果：(‘D:/保存的图片‘, ‘571711894929‘, ‘.png‘)