B. Alyona and a tree
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二分+dfs序+前缀和+瞎几把yy
#include "a.h" int n; aLL a; struct edge { int to, nx, w; } e[N << 1]; arr fi; int ce = 1; aLL sum, ans; aLL vec, up, down, res; ll tot = 1; ll rs = 0; inline void add(int u, int v, int w) { e[++ce] = edge{v, fi[u], w}; fi[u] = ce; } void dfs(int x) { if (fi[x] == -1) { rs = res[x]; rs += up[x], rs -= down[x]; ans[x] = rs; return; } for (int i = fi[x]; i != -1; i = e[i].nx) { int v = e[i].to, w = e[i].w; sum[++tot] = sum[tot - 1] + w; int p = lower_bound(sum + 1, sum + 1 + tot, sum[tot] - a[v]) - sum; if (tot - 1 >= p) up[vec[tot - 1]]++, down[vec[p - 1]]++; vec[tot] = v; dfs(v); tot--; res[x] += rs; rs = 0; } rs = res[x]; rs += up[x], rs -= down[x]; ans[x] = rs; } int main() { // file("test"); while (~scanf("%d", &n)) { me(fi, -1); For(i, 1, n) sdf(a[i]); For(i, 2, n) { int x, y; sdf(x), sdf(y); add(x, i, y); } vec[1] = 1; sum[1] = 0; dfs(1); For(i, 1, n) printf("%d ", ans[i]); } return 0; }
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Alyona and a tree CodeForces - 739B (线段树合并)