poj1426 Find The Multiple (DFS)

Posted zhgyki

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了poj1426 Find The Multiple (DFS)相关的知识,希望对你有一定的参考价值。

Find The Multiple
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 41845   Accepted: 17564   Special Judge

Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input

2
6
19
0

Sample Output

10
100100100100100100
111111111111111111

Source

题意:找出一个最小的由1或者0组成的十进制数能整除n
题解:dfs,一开始看题目说十进制数会达到100位,其实不会,在longlong的范围内,下次遇到这种可以直接打表找一下规律
代码:
#include<iostream>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> PII;
const ll mod=998244353;
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
//head
#define MAX 1000
int n;
int flag;
void dfs(int cur,ll sum)
{
    if(cur==19)return ;
    if(flag) return ;
   if(sum%n==0&&sum!=0)
   {
       flag=1;
       cout<<sum<<endl;
       return ;
   }
   else
    dfs(cur+1,sum*10),dfs(cur+1,sum*10+1);
}
int main()
{
      cin.tie(0);
    cout.tie(0);
    ios::sync_with_stdio(0);
    while(cin>>n)
    {
        if(n==0)break;
        flag=0;
        dfs(0,1);
    }
    return 0;
}

 

以上是关于poj1426 Find The Multiple (DFS)的主要内容,如果未能解决你的问题,请参考以下文章

POJ - 1426 Find The Multiple

广搜+打表 POJ 1426 Find The Multiple

搜索POJ1426:Find The Multiple

POJ 1426 - Find The Multiple - [DP][BFS]

POJ1426Find The Multiple[BFS]

poj1426 Find The Multiple (DFS)