Going in Cycle!! UVA - 11090(二分+判断环路 )

Posted wtsruvf

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Going in Cycle!! UVA - 11090(二分+判断环路 )相关的知识,希望对你有一定的参考价值。

题意:

  给定一个n个点m条边的加权有向图,求平均权值最小的回路

解析:

  首先肯定是想到找出环路  然后。。呵。。呵。。呵呵。。。

  显然不现实!!

  二分大法好 。。。。去猜结果 然后带入验证 。。。真是的。。很过分!

技术分享图片

嗯! 是的!

#include <iostream>
#include <cstdio>
#include <sstream>
#include <cstring>
#include <map>
#include <set>
#include <vector>
#include <stack>
#include <queue>
#include <algorithm>
#include <cmath>
#define rap(i, a, n) for(int i=a; i<=n; i++)
#define MOD 2018
#define LL long long
#define ULL unsigned long long
#define Pair pair<int, int>
#define mem(a, b) memset(a, b, sizeof(a))
#define _  ios_base::sync_with_stdio(0),cin.tie(0)
//freopen("1.txt", "r", stdin);
using namespace std;
const int maxn = 10010, INF = 0x7fffffff;
int head[maxn], vis[maxn], ans[maxn];
double d[maxn];
int cnt, n, m;
struct node
{
    int v, next;
    double w;
}Node[maxn];

void add(int u, int v, double w)
{
    Node[cnt].v = v;
    Node[cnt].w = w;
    Node[cnt].next = head[u];
    head[u] = cnt++;
}

int spfa(int s)
{
    for(int i=0; i<=n; i++) d[i] = INF;
    mem(ans, 0);
    mem(vis, 0);
    queue<int> Q;
    Q.push(s);
    vis[s] = 1;
    d[s] = 0;
    while(!Q.empty())
    {
        int u = Q.front(); Q.pop();
        vis[u] = 0;
        for(int i=head[u]; i!=-1; i=Node[i].next)
        {
            node e = Node[i];
            if(d[e.v] > d[u] + e.w)
            {
                d[e.v] = d[u] + e.w;
                if(!vis[e.v])
                {
                    Q.push(e.v);
                    vis[e.v] = 1;
                    if(++ans[e.v] >= n) return 1;
                }
            }
        }
    }
    return 0;
}

bool check(double x)
{
    bool flag = 0;
    for(int i=0; i<cnt; i++)
        Node[i].w -= x;

    for(int i=1; i<=n; i++)
        if(spfa(i))
            flag = 1;
    for(int i=0; i<cnt; i++)
        Node[i].w += x;
    return flag;
}

void init()
{
    mem(head, -1);
    cnt = 0;
}

int main()
{
    int T, kase = 0;
    scanf("%d", &T);
    while(T--)
    {
        init();
        int u, v;
        double w, x = 0, y = 0;
        scanf("%d%d", &n, &m);
        for(int i=0; i<m; i++)
        {
            scanf("%d%d%lf", &u, &v, &w);
            add(u, v, w);
            y = max(y, w);
        }
        printf("Case #%d: ",++kase);
        if(!check(y+1)) printf("No cycle found.
");
        else
        {
            while(y - x > 1e-3)
            {
                double mid = x + (y-x)/(double)2;
                if(check(mid)) y = mid;
                else x = mid;
            }
            printf("%.2lf
",x);
        }
    }

    return 0;
}

 

以上是关于Going in Cycle!! UVA - 11090(二分+判断环路 )的主要内容,如果未能解决你的问题,请参考以下文章

UVA - 11090 Going in Cycle!!

UVA11090 Going in Cycle!! [spfa负环]

Going in Cycle!! UVA - 11090(二分+判断环路 )

UVA11090 Going in Cycle!!

H - Going in Cycle!! (UVA - 11090)

UVa 11090 Going in Cycle!! (Bellman_Ford)