832. Flipping an Image

Posted 2020-12-26 gsz-

题目描述：

Given a binary matrix A, we want to flip the image horizontally, then invert it, and return the resulting image.

To flip an image horizontally means that each row of the image is reversed.  For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].

To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0. For example, inverting [0, 1, 1] results in [1, 0, 0].

Example 1:

Input: [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]

Example 2:

Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]

Notes:

• 1 <= A.length = A[0].length <= 20
• 0 <= A[i][j] <= 1

解题思路：

c++有个reverse函数可以实现容器反转，我这里没有用，直接遍历每个vector，交换元素。

题目不难，但是一直没能实现功能，最终发现是for(auto vec : A)的原因，应该使用for (auto &vec : A)。

代码：

 1 class Solution {
 2 public:
 3     vector<vector<int>> flipAndInvertImage(vector<vector<int>>& A) {
 4         for (auto& vec : A) {
 5             int i = 0; 
 6             int j = vec.size() - 1;
 7             while (i <= j) {
 8                 int tmp = !vec[j];
 9                 vec[j] = !vec[i];
10                 vec[i] = tmp;
11                 ++i;
12                 --j;
13             }
14         }
15         return A;
16     }
17 };