取嵌套列表中的元素

Posted 2020-12-26 python-t

b=[1,2,3,[3,4,5,3,[23,23,21,3]],3,4,[32,4,3,3]]
思路：定义函数
     遍历列表，如果不是列表类型，取出
                 是列表，调用函数

b=[1,2,3,[3,4,5,3,[23,23,21,3]],3,4,[32,4,3,3]]
c=[]
def f(li_st):
    for i in li_st:
        if type(i) != list:
            c.append(i)
        else:
            f(i)
f(b)
print(c)

[1, 2, 3, 3, 4, 5, 3, 23, 23, 21, 3, 3, 4, 32, 4, 3, 3]