三级菜单
Posted yd2018
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用递归实现：
menu = { ‘北京‘: { ‘海淀‘: { ‘五道口‘: { ‘soho‘: {}, ‘网易‘: {}, ‘google‘: {} }, ‘中关村‘: { ‘爱奇艺‘: {}, ‘汽车之家‘: {}, ‘youku‘: {}, }, ‘上地‘: { ‘百度‘: {}, }, }, ‘昌平‘: { ‘沙河‘: { ‘老男孩‘: {}, ‘北航‘: {}, }, ‘天通苑‘: {}, ‘回龙观‘: {}, }, ‘朝阳‘: {}, ‘东城‘: {}, }, ‘上海‘: { ‘闵行‘: { "人民广场": { ‘炸鸡店‘: {} } }, ‘闸北‘: { ‘火车战‘: { ‘携程‘: {} } }, ‘浦东‘: {}, }, ‘山东‘: {}, } def threeMenu(dic): while 1: for k in dic: print(k) key = input(‘输入城市(按b返回上一层,按q退出)：‘) if key == ‘b‘ or key == ‘q‘: return key elif key in dic.keys() and dic[key]: ret = threeMenu(dic[key]) if ret == ‘q‘: return ret elif (not dic.get(key)) or (not dic[key]): continue
menu = { ‘北京‘: { ‘海淀‘: { ‘五道口‘: { ‘soho‘: {}, ‘网易‘: {}, ‘google‘: {} }, ‘中关村‘: { ‘爱奇艺‘: {}, ‘汽车之家‘: {}, ‘youku‘: {}, }, ‘上地‘: { ‘百度‘: {}, }, }, ‘昌平‘: { ‘沙河‘: { ‘老男孩‘: {}, ‘北航‘: {}, }, ‘天通苑‘: {}, ‘回龙观‘: {}, }, ‘朝阳‘: {}, ‘东城‘: {}, }, ‘上海‘: { ‘闵行‘: { "人民广场": { ‘炸鸡店‘: {} } }, ‘闸北‘: { ‘火车战‘: { ‘携程‘: {} } }, ‘浦东‘: {}, }, ‘山东‘: {}, } def threeMenu(dic): while 1: for k in dic: print(k) # 北京 上海 山东 key = input(‘输入城市(按b返回上一层,按q退出)：‘) # 假设输入 北京 if key == ‘b‘ or key == ‘q‘: return key elif key in dic.keys() and dic[key]: ret = threeMenu(dic[key]) # ---------------------------------- 调用 if ret == ‘q‘: return ret elif (not dic.get(key)) or (not dic[key]): continue -------------------------------------------------------------------------------------------------------------------------------------------------- dic = { ‘海淀‘: { ‘五道口‘: { ‘soho‘: {}, ‘网易‘: {}, ‘google‘: {} }, ‘中关村‘: { ‘爱奇艺‘: {}, ‘汽车之家‘: {}, ‘youku‘: {}, }, ‘上地‘: { ‘百度‘: {}, }, }, ‘昌平‘: { ‘沙河‘: { ‘老男孩‘: {}, ‘北航‘: {}, }, ‘天通苑‘: {}, ‘回龙观‘: {}, }, ‘朝阳‘: {}, ‘东城‘: {}, }, def threeMenu(dic): while 1: for k in dic: print(k) # 海淀 昌平 朝阳 东城 key = input(‘输入城市(按b返回上一层,按q退出)：‘) # 假设输入 昌平 if key == ‘b‘ or key == ‘q‘: return key elif key in dic.keys() and dic[key]: ret = threeMenu(dic[key]) # ---------------------------------- 调用 回来的时候 ret = b if ret == ‘q‘: return ret elif (not dic.get(key)) or (not dic[key]): continue -------------------------------------------------------------------------------------------------------------------------------------------------- dic = { ‘沙河‘: { ‘老男孩‘: {}, ‘北航‘: {}, }, ‘天通苑‘: {}, ‘回龙观‘: {}, }, def threeMenu(dic): while 1: for k in dic: print(k) # 沙河 天通苑 回龙观 key = input(‘输入城市(按b返回上一层,按q退出)：‘) # 假设输入 回龙观(一直继续) 输入‘b’ if key == ‘b‘ or key == ‘q‘: return key # return ‘b‘ elif key in dic.keys() and dic[key]: ret = threeMenu(dic[key]) if ret == ‘q‘: return ret elif (not dic.get(key)) or (not dic[key]): continue
用堆栈实现：
menu = { ‘北京‘: { ‘海淀‘: { ‘五道口‘: { ‘soho‘: {}, ‘网易‘: {}, ‘google‘: {} }, ‘中关村‘: { ‘爱奇艺‘: {}, ‘汽车之家‘: {}, ‘youku‘: {}, }, ‘上地‘: { ‘百度‘: {}, }, }, ‘昌平‘: { ‘沙河‘: { ‘老男孩‘: {}, ‘北航‘: {}, }, ‘天通苑‘: {}, ‘回龙观‘: {}, }, ‘朝阳‘: {}, ‘东城‘: {}, }, ‘上海‘: { ‘闵行‘: { "人民广场": { ‘炸鸡店‘: {} } }, ‘闸北‘: { ‘火车战‘: { ‘携程‘: {} } }, ‘浦东‘: {}, }, ‘山东‘: {}, } l = [menu] while l: for k in l[-1]: print(k) key = input(‘输入城市(按b返回上一层,按q退出)：‘) if key in l[-1].keys() and l[-1][key]: l.append(l[-1][key]) elif key == ‘b‘: l.pop() elif key == ‘q‘: break else: continue
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