初识splay

Posted 2020-12-25 chaoswr

　　这东西都没什么板子着实让我很难受啊，只能到网上抄抄补补，

　　记下两个用到的博客

https://blog.csdn.net/clove_unique/article/details/50630280

https://blog.csdn.net/ophunter_lcm/article/details/18157185

 　　BZOJ 3224

　　复制粘贴？...

  1 #include <iostream>
  2 #include <string.h>
  3 #include <cstdio>
  4 #include <vector>
  5 #include <queue>
  6 #include <math.h>
  7 #include <string>
  8 #include <algorithm>
  9 #include <time.h>
 10 
 11 #define SIGMA_SIZE 26
 12 #define lson rt<<1
 13 #define rson rt<<1|1
 14 #define lowbit(x) (x&-x)
 15 #define foe(i, a, b) for(int i=a; i<=b; i++)
 16 #define fo(i, a, b) for(int i=a; i<b; i++);
 17 #pragma warning ( disable : 4996 )
 18 
 19 using namespace std;
 20 typedef long long LL;
 21 inline LL LMax(LL a, LL b) { return a>b ? a : b; }
 22 inline LL LMin(LL a, LL b) { return a>b ? b : a; }
 23 inline LL lgcd(LL a, LL b) { return b == 0 ? a : lgcd(b, a%b); }
 24 inline LL llcm(LL a, LL b) { return a / lgcd(a, b)*b; }  //a*b = gcd*lcm
 25 inline int Max(int a, int b) { return a>b ? a : b; }
 26 inline int Min(int a, int b) { return a>b ? b : a; }
 27 inline int gcd(int a, int b) { return b == 0 ? a : gcd(b, a%b); }
 28 inline int lcm(int a, int b) { return a / gcd(a, b)*b; }  //a*b = gcd*lcm
 29 const LL INF = 0x3f3f3f3f3f3f3f3f;
 30 const LL mod = 1000000007;
 31 const double eps = 1e-8;
 32 const int inf = 0x3f3f3f3f;
 33 const int maxk = 1e6 + 5;
 34 const int maxn = 1e5 + 5;
 35 
 36 int Size, root;
 37 int ch[maxn<<2][2];
 38 int f[maxn<<2];
 39 int key[maxn<<2];
 40 int cnt[maxn<<2];
 41 int siz[maxn<<2];
 42 
 43 inline void clear(int x)
 44 { ch[x][0] = ch[x][1] = f[x] = cnt[x] = key[x] = siz[x] = 0; }
 45 
 46 //判断当前点是它父节点的左儿子还是右儿子
 47 inline int get(int x)
 48 { return ch[f[x]][1] == x; }
 49 
 50 //更新当前点size值(用于修改之后)
 51 inline void update(int x)
 52 {
 53     if (x) {
 54         siz[x] = cnt[x];
 55         if (ch[x][0]) siz[x] += siz[ch[x][0]];
 56         if (ch[x][1]) siz[x] += siz[ch[x][1]];
 57     }
 58 }
 59 
 60 inline void rotate(int x)
 61 {
 62     int old = f[x], oldf = f[old], which = get(x);
 63     ch[old][which] = ch[x][which^1]; f[ch[old][which]] = old;
 64     f[old] = x; ch[x][which^1] = old;
 65     f[x] = oldf;
 66     if (oldf)
 67         ch[oldf][ch[oldf][1]==old] = x;
 68     update(old); update(x);
 69 }
 70 
 71 inline void splay(int x)
 72 {
 73     for( int fa; (fa=f[x]); rotate(x))
 74         if ( f[fa] )
 75             rotate((get(x)==get(fa) ? fa : x));
 76     root = x;
 77 }
 78 
 79 inline void insert(int v)
 80 {
 81     if ( root == 0 )
 82     { 
 83         Size++; ch[Size][0] = ch[Size][1] = f[Size] = 0; key[Size] = v;
 84         cnt[Size] = 1; siz[Size] = 1; root = Size; return;
 85     }
 86 
 87     int now = root, fa = 0;
 88     while (1)
 89     {
 90         if (key[now] == v) {
 91             cnt[now]++;
 92             update(now); update(fa);
 93             splay(now);
 94             break;
 95         }
 96         fa = now;
 97         now = ch[now][key[now]<v];
 98         if (now == 0) {
 99             Size++;
100             ch[Size][0] = ch[Size][1] = 0;
101             key[Size] = v; siz[Size] = 1;
102             cnt[Size] = 1; f[Size] = fa;
103             ch[fa][key[fa]<v] = Size;
104             update(fa);
105             splay(Size);
106             break;
107         }
108     }
109 }
110 
111 inline int find(int v)
112 {
113     int ans = 0, now = root;
114     while (1)
115     {
116         if ( v < key[now] )
117             now = ch[now][0];
118         else {
119             ans += (ch[now][0] ? siz[ch[now][0]] : 0);
120             if ( v == key[now] ) { splay(now); return ans+1; }
121 
122             ans += cnt[now];
123             now = ch[now][1];
124         }
125     }
126 }
127 
128 inline int findx(int x)
129 {
130     int now = root;
131     while (1)
132     {
133         if ( ch[now][0] && x <= siz[ch[now][0]] )
134             now = ch[now][0];
135         else {
136             int tmp = ( ch[now][0] ? siz[ch[now][0]] : 0) + cnt[now];
137 
138             if ( x <= tmp )
139                 return key[now];
140             x -= tmp;
141             now = ch[now][1];
142         }
143     }
144 }
145 
146 inline int pre()
147 {
148     int now = ch[root][0];
149     while ( ch[now][1] ) now = ch[now][1];
150     return now;
151 }
152 
153 inline int next()
154 {
155     int now = ch[root][1];
156     while ( ch[now][0] ) now = ch[now][0];
157     return now;
158 }
159 
160 
161 inline void del(int x) {
162     int whatever = find(x);
163     if (cnt[root]>1) { cnt[root]--; return; }
164     //Only One Point
165     if (!ch[root][0] && !ch[root][1]) { clear(root); root = 0; return; }
166     //Only One Child
167     if (!ch[root][0]) {
168         int oldroot = root; root = ch[root][1]; f[root] = 0; clear(oldroot); return;
169     }
170     else if (!ch[root][1]) {
171         int oldroot = root; root = ch[root][0]; f[root] = 0; clear(oldroot); return;
172     }
173     //Two Children
174     int leftbig = pre(), oldroot = root;
175     splay(leftbig);
176     f[ch[oldroot][1]] = root;
177     ch[root][1] = ch[oldroot][1];
178     clear(oldroot);
179     update(root);
180     return;
181 }
182 
183 int main()
184 {
185     int n, opt, x;
186     scanf("%d", &n);
187     for (int i = 1; i <= n; ++i) {
188         scanf("%d%d", &opt, &x);
189         switch (opt) {
190         case 1: insert(x); break;
191         case 2: del(x); break;
192         case 3: printf("%d
", find(x)); break;
193         case 4: printf("%d
", findx(x)); break;
194         case 5: insert(x); printf("%d
", key[pre()]); del(x); break;
195         case 6: insert(x); printf("%d
", key[next()]); del(x); break;
196         }
197     }
198 
199 
200     return 0;
201 }

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