Max Sum
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Problem Description
Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.
Code
#include<stdio.h> int main() { int t,n,i,j; int a; int sum,maxsum,start,end,temp; scanf("%d",&t); i=1; while(i<=t) { scanf("%d",&n); sum=0,maxsum=-1001,start=0,end=0,temp=1; for(j=0;j<n;j++) { scanf("%d",&a); sum += a; if(sum>maxsum) { maxsum=sum; start=temp; end=j+1; } if(sum<0) { sum=0; temp=j+2; } } printf("Case %d: ",i); printf("%d %d %d ",maxsum,start,end); if(i!=t) printf(" "); i++; } return 0; }
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