计算s=2+22+222+2222......的值

Posted 2020-12-18 byczyz

/*计算s=2+22+222+2222......的值*/
//验证:n=5,s=2+22+222+2222+22222=24690
#include <stdio.h>
int main(){
    int i,n,a=0,s=0;
    printf("计算s=2+22+222+2222+....的值,现在请你输入n的值:");
    scanf("%d",&n);
    for(i=1;i<=n;i++){
        a=a*10+2;
        s=s+a;
    }
    printf("%d
",s);
    return 0;
}