字典取值

Posted 2020-12-14 qd1228

#字典取值
score = (90,89,78)
d = {"name":"张三","sex":‘男‘,‘score‘:score}
#取字典的key
for  k in d.keys():
    print(k)
#取字典的value
for v in d.values():
    print(v)
#同时取字典的key value
for k,v in d.items():
    print(k,v)

#练习题
No = [1001,1002,1003,1004]
names = [‘张三‘,‘李四‘,‘王五‘,‘赵六‘]
#将上面的list合并成一个字典
#方法一：
d = {str(No[i]):names[i] for i in range(len(No))}
print(d)
#方法二：
d1= {n:names[No.index(n)] for n in No}
print(d1)
#生成新的list
kk = [item+‘ss‘ for item in names]
print(kk)