django __path__使用

Posted 2020-12-11 fmaj7

def get_commands():
    """
    Returns a dictionary mapping command names to their callback applications.

    This works by looking for a management.commands package in django.core, and
    in each installed application -- if a commands package exists, all commands
    in that package are registered.

    Core commands are always included. If a settings module has been
    specified, user-defined commands will also be included.

    The dictionary is in the format {command_name: app_name}. Key-value
    pairs from this dictionary can then be used in calls to
    load_command_class(app_name, command_name)

    If a specific version of a command must be loaded (e.g., with the
    startapp command), the instantiated module can be placed in the
    dictionary in place of the application name.

    The dictionary is cached on the first call and reused on subsequent
    calls.
    """
    commands = {name: ‘django.core‘ for name in find_commands(upath(__path__[0]))}

    if not settings.configured:
        return commands

    for app_config in reversed(list(apps.get_app_configs())):
        path = os.path.join(app_config.path, ‘management‘)
        commands.update({name: app_config.name for name in find_commands(path)})

    return commands

　　说明：只有在__init__.py才能使用__path__，此对象表示当前目录路径，如下：

[‘C:\Users\Administrator\Envs\gz_monitor\lib\site-packages\django‘]
[‘E:\Mypj\monitor\apps\flowmgr‘]