tarjan 算法求无向图的桥_板子

Posted 2020-12-09 jaszzz

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<vector>
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using namespace std;
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const int SIZE = 100010;
int head[SIZE], ver[SIZE * 2], Next[SIZE * 2];
int dfn[SIZE], low[SIZE];
int n, m, tot, num;
bool bridge[SIZE * 2];
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void add(int x, int y) {
    ver[++tot] = y, Next[tot] = head[x], head[x] = tot;
}
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void tarjan(int x, int in_edge) {
    dfn[x] = low[x] = ++num;
    for (int i = head[x]; i; i = Next[i]) {
        int y = ver[i];
        if (!dfn[y]) {
            tarjan(y, i);
            low[x] = min(low[x], low[y]);
            if (low[y] > dfn[x])
                bridge[i] = bridge[i ^ 1] = true;
        }
        else if (i != (in_edge ^ 1))
            low[x] = min(low[x], dfn[y]);
    }
}
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int main() {
    // [[0,1],[1,2],[2,0],[1,3]]
    cin >> n >> m;
    tot = 1;
    for (int i = 1; i <= m; i++) {
        int x, y;
        scanf("%d%d", &x, &y);
        add(x, y), add(y, x);
    }
    for (int i = 1; i <= n; i++)
        if (!dfn[i]) tarjan(i, 0);
    for (int i = 2; i < tot; i += 2)
        if (bridge[i])
            printf("%d %d
", ver[i ^ 1], ver[i]);
}