django url路由

Posted 2020-12-07 ch2020

 1 1创建项目    first_pro
 2 2创建app    app01
 3 做一个登录页面的web项目,浏览器输入一个网址得到一个web页面
 4 
 5 用户:    http:127.0.0.1:8001/login/
 6 
 7 1urls.py
 8 from django.conf.urls import url from django.contrib import admin from app01 import views
 9 
10 urlpatterns = [
11 # url(r‘^admin/‘, admin.site.urls),
12 url(r‘^index/‘, views.index),    #配置路径,r‘^/index/‘,这个前置导航斜杠不需要添加.
13 ]
14 
15 2写逻辑视图
16 from django.shortcuts import render,HttpResponse # Create your views here.
17 
18 def index(request): print(request.method) #‘POST‘ ‘GET‘ if request.method == ‘GET‘:
19 return render(request,‘login.html‘) else:
20 # print(request.GET) print(request.POST)
21 username = request.POST.get(‘username‘) password = request.POST.get(‘password‘)
22 if username == ‘dazhuang‘ and password == ‘123‘: return HttpResponse(‘登录成功!‘)
23 else:
24 return HttpResponse(‘登录失败!‘)
25 
26 3创建html文件
27 在templates文件夹中创建一个login.html文件