HDU 1012 u Calculate e(简单阶乘计算)

Posted yinbiao

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了HDU 1012 u Calculate e(简单阶乘计算)相关的知识,希望对你有一定的参考价值。

传送门:

http://acm.hdu.edu.cn/showproblem.php?pid=1012

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 52607    Accepted Submission(s): 24106


Problem Description
A simple mathematical formula for e is

技术分享图片

where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

 

Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
 

 

Source
 分析:
没有什么好说的
水题
code:
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
int f(int x)
{
    if(x==0)
        return 1;
    if(x==1)
        return 1;
    LL sum=1;
    for(int i=1;i<=x;i++)
    {
        sum*=i;
    }
    return sum;
}
int main()
{
    printf("n e
");
    printf("- -----------
");
    printf("0 1
1 2
2 2.5
");
    for(int i=3;i<=9;i++)
    {
        double result=0;
        for(int j=0;j<=i;j++)
        {
            result+=(1.0/(f(j)*1.0));
        }
        printf("%d %0.9lf
",i,result);
    }
    return 0;
}

 









以上是关于HDU 1012 u Calculate e(简单阶乘计算)的主要内容,如果未能解决你的问题,请参考以下文章

HDU 1012 u Calculate e暴力打表,水

Hdu oj 1012 u Calculate e

1012 u Calculate e

HDU OJ u Calculate e

HDU OJ u Calculate e

HDU 1008 u Calculate e